def reverse(head): if head == None or head.next == None: return head psuhead = ListNode(-1) while head: nexthead = head.next head.next = psuhead.next psuhead.next = head head = nexthead head = psuhead.next del psuhead return head
【剑指offer】Q16：翻转链表,布布扣,bubuko.com
原文地址：http://blog.csdn.net/shiquxinkong/article/details/37323291
