码迷,mamicode.com
首页 > 其他好文 > 详细

LeetCode#125 Valid Palindrome

时间:2015-07-21 12:15:25      阅读:102      评论:0      收藏:0      [点我收藏+]

标签:

Problem Definition:

Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.

For example,
"A man, a plan, a canal: Panama" is a palindrome.
"race a car" is not a palindrome.

Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.

For the purpose of this problem, we define empty string as valid palindrome.

 
Solution 1: Using regular expression.
1 def isPalindrome(self, s):
2         p=re.compile(\w)
3         arr=p.findall(s)
4         n=len(arr)/2
5         for i in range(n):
6             if arr[i].upper()!=arr[n-1-i].upper():
7                 return False
8         return True

 

Solution 2: A simpler way of using regular expression.

1 def isPalindrome(self, s):
2         s = re.sub("[^A-Za-z0-9]", "", s).lower()  #可以换成‘\W‘
3         return s == s[::-1]

 

Solution 3: Just traverse the string.

 

1 def isPalindrome(s):
2         s1 = ‘‘.join(ch for ch in s if ch.isalnum()).lower()
3         return s1 == s1[::-1]

 

 

 

 

 

 

 
 

LeetCode#125 Valid Palindrome

标签:

原文地址:http://www.cnblogs.com/acetseng/p/4663947.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!