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[leetcode] Evaluate Reverse Polish Notation

时间:2014-07-08 22:28:14      阅读:176      评论:0      收藏:0      [点我收藏+]

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Evaluate the value of an arithmetic expression in Reverse Polish Notation.

Valid operators are +-*/. Each operand may be an integer or another expression.

Some examples:

  ["2", "1", "+", "3", "*"] -> ((2 + 1) * 3) -> 9
  ["4", "13", "5", "/", "+"] -> (4 + (13 / 5)) -> 6

https://oj.leetcode.com/problems/evaluate-reverse-polish-notation/

 

思路:stack的经典题目,遇到数字压栈,遇到符号出栈两个计算再入栈。

 

import java.util.Stack;

public class Solution {
    public int evalRPN(String[] tokens) {
        Stack<Integer> stack = new Stack<Integer>();
        int a, b;
        for (int i = 0; i < tokens.length; i++) {
            if (tokens[i].equals("+")) {
                a = stack.pop();
                b = stack.pop();
                stack.push(b + a);
            } else if (tokens[i].equals("-")) {
                a = stack.pop();
                b = stack.pop();
                stack.push(b - a);
            } else if (tokens[i].equals("*")) {
                a = stack.pop();
                b = stack.pop();
                stack.push(b * a);
            } else if (tokens[i].equals("/")) {
                a = stack.pop();
                b = stack.pop();
                stack.push(b / a);
            } else {
                stack.push(Integer.parseInt(tokens[i]));
            }
        }

        return stack.pop();
    }

    public static void main(String[] args) {
        System.out.println(new Solution().evalRPN(new String[] { "2", "1", "+",
                "3", "*" }));
        System.out.println(new Solution().evalRPN(new String[] { "4", "13",
                "5", "/", "+" }));
    }

}

 

[leetcode] Evaluate Reverse Polish Notation,布布扣,bubuko.com

[leetcode] Evaluate Reverse Polish Notation

标签:style   blog   http   java   color   for   

原文地址:http://www.cnblogs.com/jdflyfly/p/3830534.html

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