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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 27954 Accepted Submission(s): 19117
/*
* 对幂取模如对37的4次方取模
* (37*37*37*37)%m
* ==(37%m*(37*37*37)%m)%m
* ==(37%m*(37%m*(37*37)%m)%m)%m
* ==(37%m*(37%m*(37%m*37%m)%m)%m)%m
*/
//求n^m%1000
s=n;
for(i=1;i<m;i++)
{
s=s*n;
s=s%1000;
}
AC代码:
#include<stdio.h>
#include<string.h>
int main()
{
int n,m,i,j,s;
while(scanf("%d%d",&n,&m)&&n!=0&&m!=0)
{
s=n;
for(i=1;i<m;i++)
{
s=s*n;
s=s%1000;
}
printf("%d\n",s);
}
return 0;
}
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原文地址:http://www.cnblogs.com/tonghao/p/4674613.html