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http://www.lintcode.com/en/problem/remove-duplicates-from-sorted-list-ii/
Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
Example
Given 1->2->3->3->4->4->5, return 1->2->5.
Given 1->1->1->2->3, return 2->3.
/**
* Definition of ListNode
* class ListNode {
* public:
* int val;
* ListNode *next;
* ListNode(int val) {
* this->val = val;
* this->next = NULL;
* }
* }
*/
class Solution{
public:
/**
* @param head: The first node of linked list.
* @return: head node
*/
ListNode * deleteDuplicates(ListNode *head) {
// write your code here
if (head == NULL || head->next == NULL) {
return head;
}
ListNode* dummy = new ListNode(0);
dummy->next = head;
head = dummy;
while (head->next != NULL && head->next->next != NULL) {
if (head->next->val == head->next->next->val) {
int val = head->next->val;
while (head->next != NULL && head->next->val == val) {
head->next = head->next->next;
}
} else {
head = head->next;
}
}
return dummy->next;
}
};
None
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LintCode - Remove Duplicates from Sorted List II Show result
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原文地址:http://blog.csdn.net/lionpku/article/details/47049447