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Codeforces Round #313 A Currency System in Geraldion

时间:2015-07-25 15:11:39      阅读:104      评论:0      收藏:0      [点我收藏+]

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              A  Currency System in Geraldion

Time Limit:2000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u
 

Description

A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cannot express a certain sum of money with any set of banknotes. Of course, they can use any number of banknotes of each value. Such sum is called unfortunate. Gerald wondered: what is the minimumunfortunate sum?

Input

The first line contains number n (1 ≤ n ≤ 1000) — the number of values of the banknotes that used in Geraldion.

The second line contains n distinct space-separated numbers a1, a2, ..., an (1 ≤ ai ≤ 106) — the values of the banknotes.

Output

Print a single line — the minimum unfortunate sum. If there are no unfortunate sums, print  - 1.

Sample Input

Input
5
1 2 3 4 5
Output
-1

 

 

一开始看到就懵了,后来弄懂的时候感觉自己有点傻逼了

题意:求n个整数不能组成的最小整数,如果都存在,输出-1.

思路:如果n个数中有1,则都能组成,输出-1,否则不能组成的最小整数1,输出1.

#include<iostream>
using namespace std;
int main()
{
    int t,a,ans=0;
     cin>>t;
 for(int i=1;i<=t;i++)
 {
     cin>>a;
     if(a==1)
     ans=1;
 }
 if(ans)
         cout<<"-1"<<endl;
else 
         cout<<"1"<<endl;
return 0;
}

 

Codeforces Round #313 A Currency System in Geraldion

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原文地址:http://www.cnblogs.com/hfc-xx/p/4675903.html

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