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Given an array of n integers where n > 1, nums,
return an array output such thatoutput[i] is
equal to the product of all the elements of nums except nums[i].
Solve it without division and in O(n).
For example, given [1,2,3,4], return [24,12,8,6].
vector<int> productExceptSelf(vector<int>& nums) {
int total=1;
int num=0;
int weizhi=-1;
for(int i=0;i<nums.size();i++)
{
if(nums[i]!=0)
total*=nums[i];
if(nums[i]==0)
{
num++;
weizhi=i;
}
}
vector<int> res(nums.size(),0);
if(num>1)
{
return res;
}
else if(num==1)
{
res[weizhi]=total;
return res;
}
else
{
for(int i=0;i<nums.size();i++)
res[i]=total/nums[i];
return res;
}
return res;
} int n=nums.size();
vector<int> res(n,1);
for(int i=0;i<n;i++)
{
if(i==0) res[i]=1;
else
res[i]=res[i-1]*nums[i-1];
}
int right=1;
for(int i=n-1;i>=0;i--)
{
res[i]*=right;
right*=nums[i];
}
return res;
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原文地址：http://blog.csdn.net/sinat_24520925/article/details/47057631
