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Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree.According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”
_______3______ / ___5__ ___1__ / \ / 6 _2 0 8 / 7 4
For example, the lowest common ancestor (LCA) of nodes 5
and 1
is 3
.
Another example is LCA of nodes 5
and 4
is 5
,
since a node can be a descendant of itself according to the LCA definition.
[思路]
深度优先搜索搜寻节点,存储节点路径。在两个路径中找到公共节点。注意不是二叉搜索树。
[代码]
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) { vector<TreeNode*> path1; vector<TreeNode*> path2; TreeNode* ret; FindPath(root,path1,p); FindPath(root,path2,q); for(int i=0 ;i<min(path1.size(),path2.size());++i){ if(path1[i]==path2[i]) ret = path1[i]; } return ret; } void FindPath(TreeNode *root,vector<TreeNode*> &path,TreeNode *find){ if(root == nullptr){ return; } if(root == find){ path.push_back(find); return; } path.push_back(root); FindPath(root->left,path,find); FindPath(root->right,path,find); path.pop_back(); } };
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[LeetCode]Lowest Common Ancestor of a Binary Tree
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原文地址:http://blog.csdn.net/ciaoliang/article/details/47065771