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Unique Path

时间:2015-07-26 12:33:00      阅读:97      评论:0      收藏:0      [点我收藏+]

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A robot is located at the top-left corner of a m x n grid (marked ‘Start‘ in the diagram below).

The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked ‘Finish‘ in the diagram below).

How many possible unique paths are there?

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Above is a 3 x 7 grid. How many possible unique paths are there?

Note: m and n will be at most 100.

 

Analyse: Dynamic Planning. Transfer function is grid[i][j] = grid[i - 1][j] + grid[i][j - 1].

Runtime: 0ms.

 1 class Solution {
 2 public:
 3     int uniquePaths(int m, int n) {
 4         vector<vector<int> > grid(m, vector<int> (n, 0));
 5         
 6         for(int i = 0; i < m; i++) 
 7             grid[i][0] = 1; //the first colume has only one path
 8         for(int j = 0; j < n; j++) 
 9             grid[0][j] = 1; // the first row has only one path
10         for(int i = 1; i < m; i++)
11             for(int j = 1; j < n; j++)
12                 grid[i][j] = grid[i - 1][j] + grid[i][j - 1];
13         
14         return grid[m - 1][n - 1];
15     }
16 };

 

Unique Path

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原文地址:http://www.cnblogs.com/amazingzoe/p/4677402.html

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