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Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is 1 -> 2 -> 3 -> 4
and you are given the third node with value 3
, the linked list should become 1 -> 2 -> 4
after calling your function.
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1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *next; 6 * ListNode(int x) : val(x), next(NULL) {} 7 * }; 8 */ 9 class Solution { 10 public: 11 void deleteNode(ListNode* node) { 12 ListNode *cur=node; 13 ListNode *post=node->next; 14 while(true){ 15 cur->val=post->val; 16 if(post->next==NULL){ 17 cur->next=NULL; 18 return; 19 }else{ 20 cur=post; 21 post=post->next; 22 } 23 } 24 } 25 };
【LeetCode】237 - Delete Node in a Linked List
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原文地址:http://www.cnblogs.com/irun/p/4678947.html