标签：水题

相遇周期

Time Limit : 1000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other)

Total Submission(s) : 12   Accepted Submission(s) : 3

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Problem Description

Input

Output

Sample Input

2
26501/6335 18468/42
29359/11479 15725/19170

Sample Output

81570078/7
5431415

参考代码：

#include<stdio.h>
int  gcd(int x,int y)  
{  
    while(x!=y)  
    {  
        if(x>y)  
        x=x-y;  
        else  
         y=y-x;  
    }  
    return x;  
}  
int lcm(int a,int b)
{
	return a/gcd(a,b)*b;
}
int main()
{
	int t;
	scanf("%d",&t);
	while(t--)
	{
		int a,b,c,d,p;
		scanf("%d/%d",&a,&b);
		p=gcd(a,b);//这行不能与下一行合并。
		a/=p;
		b/=p;
		scanf("%d/%d",&c,&d);
		p=gcd(c,d);
		c/=p;
		d/=p;
		if(gcd(b,d)==1)
		    printf("%d\n",lcm(a,c));
        else 
            printf("%d/%d\n",lcm(a,c),gcd(b,d));
	}
	return 0;
}

HDU 1713 -相遇周期

标签：水题

原文地址：http://blog.csdn.net/luwhere/article/details/47073097