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| Time Limit: 1000MS | Memory Limit: 32768KB | 64bit IO Format: %I64d & %I64u |
Description
Input
Output
Sample Input
8 389 207 155 300 299 170 158 65
Sample Output
2
子序列:
#include <cstdio>
#include <cstring>
#include <cmath>
#include <algorithm>
using namespace std;
//动态分析
/* |
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*/
//从右到左呈现递增趋势
//运用最长上升子序列
int a[3005];
int dp[3005];
int main(){
int n;
//freopen("D://imput.txt","r",stdin);
while(~scanf("%d",&n)){
for(int i=1;i<=n;i++){
scanf("%d",&a[i]);
}
memset(dp,0,sizeof(dp));
int reco=1;
for(int i=1;i<=n;i++){
dp[i]=1;
for(int j=1;j<i;j++){
if(a[j]<a[i]){
dp[i]=max(dp[i],dp[j]+1);
}
}
reco=max(reco,dp[i]);
}
printf("%d\n",reco);
}
return 0;
}
#include <cstdio>
#include <cstring>
#include <algorithm>
int a[3005],dp[3005],keep[3005];
//贪心算法,每个阶段寻找最优解(正解时间比动态规划要少空间消耗更大)
using namespace std;
int main(){
int cur=1,res=0,rec,reco,n;
//freopen("D://output.txt","r",stdin);
while(~scanf("%d",&n)){
if(n==0)continue;
scanf("%d",&a[1]);reco=cur=keep[1]=dp[1]=1;
for(int i=2;i<=n;i++){
scanf("%d",&a[i]);rec=0;
for(int k=1;k<=cur;k++){
if(a[res=keep[k]]>=a[i])
dp[i]=dp[rec||a[rec]>a[res]? res:rec=res];//将导弹加在最低数的尾部
}
if(a[rec]<a[i]) keep[dp[i]=++cur]=i;
else keep[dp[i]=dp[rec]]=i;
reco=max(reco,dp[i]);//比较,得出最多系统
//printf("[%d]\n",dp[i]);
}
printf("%d\n",reco);
}
return 0;
}
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原文地址:http://blog.csdn.net/qq_18661257/article/details/47080343