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经典尺取法,复杂度O(n)。
1 #include <iostream> 2 #include <cstring> 3 #include <cstdio> 4 using namespace std; 5 6 const int INF = 999999; 7 const int N = 100000; 8 int a[N]; 9 10 int main () 11 { 12 int t; 13 scanf("%d", &t); 14 while ( t-- ) 15 { 16 int n, s; 17 scanf("%d%d", &n, &s); 18 for ( int i = 0; i < n; i++ ) scanf("%d", a + i); 19 int p = 0, q = 0, sum = 0, len = INF; 20 while ( 1 ) 21 { 22 while ( q < n && sum < s ) 23 { 24 sum += a[q++]; 25 } 26 if ( sum < s ) break; 27 len = min( len, q - p ); 28 sum -= a[p++]; 29 } 30 if ( len == INF ) len = 0; 31 printf("%d\n", len); 32 } 33 return 0; 34 }
二分也可以做,复杂度多了个log。
1 #include <algorithm> 2 #include <iostream> 3 #include <cstring> 4 #include <cstdio> 5 using namespace std; 6 7 typedef long long ll; 8 const int INF = 999999; 9 const int N = 100001; 10 ll sum[N]; 11 12 int main () 13 { 14 int t; 15 scanf("%d", &t); 16 while ( t-- ) 17 { 18 int n, s; 19 scanf("%d%d", &n, &s); 20 sum[0] = 0; 21 for ( int i = 1; i <= n; i++ ) 22 { 23 scanf("%lld", sum + i); 24 sum[i] += sum[i - 1]; 25 } 26 int len = INF; 27 for ( int i = n; i > 0; i-- ) 28 { 29 if ( sum[i] < s ) break; 30 int pos = upper_bound( sum, sum + i, sum[i] - s ) - sum; 31 if ( pos != i ) 32 { 33 len = min( len, i - pos + 1 ); 34 } 35 } 36 if ( len == INF ) len = 0; 37 printf("%d\n", len); 38 } 39 return 0; 40 }
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原文地址:http://www.cnblogs.com/huoxiayu/p/4679935.html