标签:poj3468
这个点POJ挂了,代码没法提交,先存到这里,明天再提交试试看。
//#define DEBUG #include <stdio.h> #define maxn 100002 #define lson l, mid, rt << 1 #define rson mid + 1, r, rt << 1 | 1 __int64 tree[maxn << 2], arr[maxn], lazy[maxn << 2]; void pushUp(int rt) { tree[rt] = tree[rt << 1] + tree[rt << 1 | 1]; } void pushDown(int l, int r, int rt) { int mid = (l + r) >> 1; tree[rt << 1] += (mid - l + 1) * lazy[rt]; tree[rt << 1 | 1] += (r - mid) * lazy[rt]; lazy[rt << 1] = lazy[rt << 1 | 1] = lazy[rt]; lazy[rt] = 0; } void build(int l, int r, int rt) { lazy[rt] = 0; if(l == r){ tree[rt] = arr[r]; return; } int mid = (l + r) >> 1; build(lson); build(rson); pushUp(rt); } void update(int left, int right, int val, int l, int r, int rt) { if(left == l && right == r){ lazy[rt] += val; tree[rt] += val * (r - l + 1); return; } //include l == r if(lazy[rt]) pushDown(l, r, rt); int mid = (l + r) >> 1; if(right <= mid) update(left, right, val, lson); else if(left > mid) update(left, right, val, rson); else{ update(left, mid, val, lson); update(mid + 1, right, val, rson); } pushUp(rt); } __int64 query(int left, int right, int l, int r, int rt) { if(lazy[rt]) pushDown(l, r, rt); if(left == l && right == r) return tree[rt]; int mid = (l + r) >> 1; if(right <= mid){ return query(left, right, lson); }else if(left > mid){ return query(left, right, rson); }else{ return query(left, mid, lson) + query(mid + 1, right, rson); } } int main() { #ifdef DEBUG freopen("../stdin.txt", "r", stdin); freopen("../stdout.txt", "w", stdout); #endif int n, q, i, a, b, c; char com[2]; while(scanf("%d%d", &n, &q) == 2){ for(i = 1; i <= n; ++i) scanf("%I64d", arr + i); build(1, n, 1); while(q--){ scanf("%s%d%d", com, &a, &b); if(com[0] == 'C'){ scanf("%d", &c); update(a, b, c, 1, n, 1); }else printf("%I64d\n", query(a, b, 1, n, 1)); } } return 0; }
标签:poj3468
原文地址:http://blog.csdn.net/chang_mu/article/details/37581635