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对原来的边(u, v) 方向定为u->v当w[u] > w[v]
最大Set是max{u到达的点集合}
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#pragma comment(linker, "/STACK:1024000000,1024000000")
#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>
using namespace std;
typedef long long ll;
#define prt(k) cout<<#k" = "<<k<<endl;
const int N = 501000;
int dp[N], g[N], w[N];
struct edge
{
int v, next;
}e[N<<1];
int head[N], mm;
void add(int u, int v)
{
e[mm].v= v;
e[mm].next = head[u];
head[u] = mm++;
}
int pa[N];
int up(int u)
{
if (~g[u]) return g[u];
g[u] = 1;
int v = pa[u];
if (w[u] > w[v]) g[u] = up(v) + 1;
return g[u];
}
int n;
pair<int, int> p[N];
int main()
{
while (scanf("%d", &n)==1) {
for (int i=1;i<=n;i++) scanf("%d", w+i), p[i]=make_pair(w[i], i);
sort(p+1, p+n+1);
mm = 0; memset(head, -1, sizeof head);
for (int i=0;i<n-1;i++) {
int u, v;
scanf("%d%d", &u, &v);
add(u, v);
add(v, u);
}
memset(dp, -1, sizeof dp);
memset(g, -1, sizeof g);
pa[1] = 1; g[1] = 1;
int ans = 1;
for (int i=n;i>=1;i--) {
int u = p[i].second;
dp[u] = 1;
for (int j=head[u];~j;j=e[j].next) {
int v = e[j].v;
if (w[u] < w[v]) dp[u] += dp[v];
}
ans = max(ans, dp[u]);
}
printf("%d\n", ans);
}
return 0;
}
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原文地址:http://blog.csdn.net/oilover/article/details/47111897