标签:leetcode unique binary search
Unique Binary Search Trees II
Given n, generate all structurally unique BST‘s (binary search trees) that store values 1...n.
For example,
Given n = 3, your program should return all 5 unique BST‘s shown below.
1 3 3 2 1 \ / / / \ 3 2 1 1 3 2 / / \ 2 1 2 3迄今为止看到的最为经典的算法,分数超过14000的好评
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector<TreeNode*> generateTrees(int n) { return helper(1, n); } vector<TreeNode*> helper(int s, int e){ if(s>e){ return vector<TreeNode*>(1, NULL); } vector<TreeNode *> res; for(int i=s; i<=e; i++){ vector<TreeNode *> left=helper(s, i-1); vector<TreeNode *> right=helper(i+1, e); for(int j=0; j<left.size(); j++){ for(int k=0; k<right.size(); k++){ TreeNode * p=new TreeNode(i); p->left=left[j]; p->right=right[k]; res.push_back(p); } } } return res; } };来自leetcode:https://leetcode.com/discuss/26330/30-ms-c-solution
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经典中的经典Unique Binary Search Trees II
标签:leetcode unique binary search
原文地址:http://blog.csdn.net/jisuanji_wjfioj/article/details/47133393