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Ice_cream's world I--hdu2120

时间:2015-07-29 22:50:37      阅读:261      评论:0      收藏:0      [点我收藏+]

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Ice_cream‘s world I

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 839    Accepted Submission(s): 488


Problem Description
ice_cream‘s world is a rich country, it has many fertile lands. Today, the queen of ice_cream wants award land to diligent ACMers. So there are some watchtowers are set up, and wall between watchtowers be build, in order to partition the ice_cream’s world. But how many ACMers at most can be awarded by the queen is a big problem. One wall-surrounded land must be given to only one ACMer and no walls are crossed, if you can help the queen solve this problem, you will be get a land.
 

 

Input
In the case, first two integers N, M (N<=1000, M<=10000) is represent the number of watchtower and the number of wall. The watchtower numbered from 0 to N-1. Next following M lines, every line contain two integers A, B mean between A and B has a wall(A and B are distinct). Terminate by end of file.
 

 

Output
Output the maximum number of ACMers who will be awarded.
One answer one line.
 

 

Sample Input
8 10
0 1
1 2
1 3
2 4
3 4
0 5
5 6
6 7
3 6
4 7
 
 
 

 

Sample Output
3
 
注意:这是一个求总共有多少环(环内有节点的不算),我们可以利用判断两节点的根节点是否相同来判断!
 
 
 
 
 1 #include<stdio.h>
 2 #include<string.h>
 3 #include<algorithm>
 4 #define maxn 10010
 5 using namespace std;
 6 
 7 int per[maxn],sum;
 8 void init()
 9 {
10     int i;
11     for(i=0;i<maxn;i++)
12     {
13         per[i]=i;//初始化数组
14     }
15 }
16 int find(int x)//查找根节点
17 {
18     int t=x;
19     while(t!=per[t])
20     t=per[t];
21 return t;
22 }
23 void join(int x,int y)
24 {
25     int fx=find(x);
26     int fy=find(y);
27     if(fx==fy)
28         sum++;//环的个数
29     else
30         per[fx]=fy;
31 }
32 int main()
33 {
34     int a,b,i,m,n;
35     while(scanf("%d%d",&a,&b)!=EOF)
36     {
37         init();
38         sum=0;
39         for(i=0;i<b;i++)
40         {
41             scanf("%d%d",&m,&n);
42             join(m,n);
43         }
44         printf("%d\n",sum);
45     }
46 return 0;
47 }

 

 
 

Ice_cream's world I--hdu2120

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原文地址:http://www.cnblogs.com/Eric-keke/p/4687497.html

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