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Description
Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings a and b of equal length are calledequivalent in one of the two cases:
As a home task, the teacher gave two strings to his students and asked to determine if they are equivalent.
Gerald has already completed this home task. Now it‘s your turn!
Input
The first two lines of the input contain two strings given by the teacher. Each of them has the length from 1 to 200 000 and consists of lowercase English letters. The strings have the same length.
Output
Print "YES" (without the quotes), if these two strings are equivalent, and "NO" (without the quotes) otherwise.
Sample Input
aaba
abaa
YES
aabb
abab
NO
Hint
In the first sample you should split the first string into strings "aa" and "ba", the second one — into strings "ab" and "aa". "aa" is equivalent to "aa"; "ab" is equivalent to "ba" as "ab" = "a" + "b", "ba" = "b" + "a".
In the second sample the first string can be splitted into strings "aa" and "bb", that are equivalent only to themselves. That‘s why string "aabb" is equivalent only to itself and to string "bbaa".
题意：给两个字符串，判断它们是否相等，相等有两种情况，一个是字符串直接相等，一个是切成长度相同的两份以后两子串相等（两种情况）
题解：直接判断行了，如果当前长度为奇数，如果不是完全相等，直接返回0，否则分两种情况判断
#include<stdio.h> #include<string.h> char a[200005],b[200005]; int juge(char *p,char *q, int len) { if(!strncmp(p,q,len)) //判断怕，p，q字符串长度是否相等 return -1; if(len%2) return 0; // 结束判断 int mid=len/2; if(juge(p,q+mid,mid)&&juge(p+mid,q,mid)) return -1; if(juge(p+mid,q+mid,mid)&&juge(p,q,mid)) return -1; } int main() { scanf("%s%s",&a,&b); if(juge(a,b,strlen(a))) printf("YES"); else printf("NO"); return 0; }
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原文地址：http://www.cnblogs.com/hfc-xx/p/4688506.html
