翻转字符串

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 char *p,*start,*end,*temp,c;

    int count = 0,i =0 ;

    p = (char *)malloc(21 * sizeof(char));

    printf("请输入要反转的字符串:\n");

    while ((c = getchar() )!= ‘\n‘) {

        *(p + count) = c;

        count++;

    }

    *(p+count)=‘\0‘;

    start = p;

    end = p+count-1; //结尾的尾0 \0

    for(i = 0; i< count/2;i++,start++,end--)

    {

        temp = *start;

        *start = *end;

        *end    = temp;

    }

    printf("%s",p);

翻转字符串

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原文地址：http://www.cnblogs.com/superrichie/p/4689642.html