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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 17887 Accepted Submission(s): 10298
1 #include <cstring> 2 #include <iostream> 3 using namespace std; 4 #define N 110; 5 int m, n, i, j; 6 7 int ac[8][2]={{0,1},{1,1},{1,0},{1,-1},{0,-1},{-1,-1},{-1,0},{-1,1}}; 8 int vis[110][110]; 9 char map[110][110]; 10 int sum = 0; 11 12 void DFS(int x, int y) 13 { 14 int nx, ny; 15 vis[x][y] = 1; 16 for(int i=0; i<8; i++) 17 { 18 nx = x + ac[i][0]; 19 ny = y + ac[i][1]; 20 if(map[nx][ny]==‘@‘&&nx>=0&&nx<m&&ny>=0&&ny<n&&vis[nx][ny]==0) 21 { 22 DFS(nx, ny); 23 } 24 } 25 } 26 27 28 int main() 29 { 30 while(~scanf("%d %d", &m, &n), m) 31 { 32 for(i=0 ; i<m; i++) 33 for(j=0; j<n; j++) 34 cin >> map[i][j]; 35 memset(vis, 0, sizeof(vis)); 36 sum = 0; 37 for(i=0; i<m; i++) 38 { 39 for(j=0; j<n; j++) 40 if(map[i][j] == ‘@‘ && !vis[i][j]) 41 { 42 DFS(i, j); 43 sum++; 44 } 45 } 46 cout << sum <<endl; 47 48 } 49 return 0; 50 }
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原文地址:http://www.cnblogs.com/fengshun/p/4689690.html