6 9 ....#. .....# ...... ...... ...... ...... ...... #@...# .#..#. 11 9 .#......... .#.#######. .#.#.....#. .#.#.###.#. .#.#..@#.#. .#.#####.#. .#.......#. .#########. ........... 11 6 ..#..#..#.. ..#..#..#.. ..#..#..### ..#..#..#@. ..#..#..#.. ..#..#..#.. 7 7 ..#.#.. ..#.#.. ###.### ...@... ###.### ..#.#.. ..#.#.. 0 0
45 59 6 13
#include<iostream>
#include<sstream>
#include<algorithm>
#include<cstdio>
#include<string.h>
#include<cctype>
#include<string>
#include<cmath>
#include<vector>
#include<stack>
#include<queue>
#include<map>
#include<set>
using namespace std;
const int INF=40;
char cnt[INF][INF];
int vis[INF][INF];
int dir[][2]= {{1,0},{0,1},{-1,0},{0,-1}};
int ans,w,h;
void dfs(int x,int y)
{
for(int i=0; i<4; i++)
{
int tx=dir[i][0]+x;
int ty=dir[i][1]+y;
if(tx>=1&&tx<=w&&ty>=1&&ty<=h&&!vis[tx][ty]&&cnt[tx][ty]=='.')
{
ans++;
vis[tx][ty]=1;
dfs(tx,ty);
}
}
return ;
}
int main()
{
while(cin>>h>>w,h+w)
{
memset(vis,0,sizeof(vis));
int si,sj;
ans=1;
for(int i=1; i<=w; i++)
scanf("%s",cnt[i]+1);
for(int i=1; i<=w; i++)
{
for(int j=1; j<=h; j++)
{
if(cnt[i][j]=='@')
{
si=i;
sj=j;
break;
}
}
}
dfs(si,sj);
cout<<ans<<endl;
}
return 0 ;
}版权声明:本文为博主原创文章,未经博主允许不得转载。
杭电 HDU 1312 Red and Black(超级简单dfs)
原文地址:http://blog.csdn.net/lsgqjh/article/details/47166289