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Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below.

For example, given the following triangle

[
     [2],
    [3,4],
   [6,5,7],
  [4,1,8,3]
]

The minimum path sum from top to bottom is 11 (i.e., 2 + 3 + 5 + 1 = 11).

解题思路：

求金字塔的最短路径，其中路径只能走下一行的相邻位置。我们将路径相叠加，有两条路径的将会选一个路径叠加较小的那条路径值。代码如下：

class Solution {
public:
    int minimumTotal(vector<vector<int>>& triangle) {
       if(triangle.size()==0) return 0;
        int n=triangle.size();
        int m=triangle[0].size();
        vector<int> temp=triangle[0];
        
        for(int i=1;i<triangle.size();i++)
        {
            temp.push_back(0);
            for(int j=0;j<triangle[i].size();j++)
            {
                if(j==0)
                {
                    temp[j]+=triangle[i][j];
                }
				else if(j==triangle[i].size()-1)
				{
					temp[j]=triangle[i-1][j-1]+triangle[i][j];
				}
                else 
                {
                    temp[j]=(triangle[i][j]+triangle[i-1][j-1])>(triangle[i][j]+triangle[i-1][j])?(triangle[i][j]+triangle[i-1][j]):(triangle[i][j]+triangle[i-1][j-1]);
                }
            }
			triangle[i]=temp;
            
        }
        sort(temp.begin(),temp.end());
        return temp[0];
    }
};

Triangle

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原文地址：http://blog.csdn.net/sinat_24520925/article/details/47185511