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【LeetCode】226 - Invert Binary Tree

时间:2015-08-02 15:04:53      阅读:73      评论:0      收藏:0      [点我收藏+]

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Invert a binary tree.

     4
   /     2     7
 / \   / 1   3 6   9
to
     4
   /     7     2
 / \   / 9   6 3   1
Trivia:
This problem was inspired by this original tweet by Max Howell:
Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.

 

 1 /**
 2  * Definition for a binary tree node.
 3  * struct TreeNode {
 4  *     int val;
 5  *     TreeNode *left;
 6  *     TreeNode *right;
 7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 8  * };
 9  */
10 class Solution {
11 public:
12     TreeNode* invertTree(TreeNode* root) {
13         if(root==NULL)
14             return NULL;
15         else{
16             TreeNode *newleft=invertTree(root->right);
17             TreeNode *newright=invertTree(root->left);
18             root->left=newleft;
19             root->right=newright;
20             return root;
21         }
22     }
23 };

 

 

【LeetCode】226 - Invert Binary Tree

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原文地址:http://www.cnblogs.com/irun/p/4695718.html

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