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题目给你一个串, 串是严格的 1 – n 的排列,里面的数是随机的
把这个串里面的数字分别输出//先预处理,对于给出的串能找到里面的最大数,再 DFS 处理
#include<iostream> #include<string> #include<algorithm> #include<cstdio> #include<cstring> #include<stack> using namespace std; bool Jug[100]; string num[55]; string str; int len,Num; stack<int> Sum; bool Dfs(int n) { if(n >= len) { if(Jug[Num] == true) return true; return false; } int a,b; if(n <len) a = str[n] - ‘0‘; if(n < len-1) b = a*10 + str[n+1] - ‘0‘; if(a==0) return false; if(Jug[a] == false && n <len) { Jug[a] = true; if(Dfs(n+1)) { Sum.push(a); return true; } Jug[a] = false; } if(b <= 50 && Jug[b] == false && n < len-1) { Jug[b] = true; if(Dfs(n+2)) { Sum.push(b); return true; } Jug[b] = false; } return false; } int main() { num[1] = "1"; for(int i = 2; i <= 50; ++i) if(i < 10) num[i] = (num[i-1] + char(i + ‘0‘)); else num[i] = (num[i-1] + char(i/10 + ‘0‘) + char (i % 10 + ‘0‘)); for(int i = 1; i <= 50; ++i) sort(num[i].begin(),num[i].end()); ////////////// while(cin >> str) { Num = 0; memset(Jug,false,sizeof(Jug)); while(!Sum.empty()) Sum.pop(); string s = str; sort(s.begin(),s.end()); for(int i = 1; i <= 50; ++i) if(s == num[i]) { Num = i; break; } //cout << Num << endl; len = str.length(); Dfs(0); while(!Sum.empty()) { cout << Sum.top() << " "; Sum.pop(); } cout << endl; } }
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原文地址:http://www.cnblogs.com/aoxuets/p/4699555.html