标签:
Given a rotated sorted array, recover it to sorted array in-place.
Have you met this question in a real interview?[4, 5, 1, 2, 3] -> [1,
2, 3, 4, 5]
In-place, O(1) extra space and O(n) time.
What is rotated array?
class Solution {
public:
void recoverRotatedSortedArray(vector<int> &nums) {
// write your code here
int len = nums.size();
if (0 == len) {
return ;
}
int t = 0;
for (int i = 0; i < len; ++i) {
if (nums[i] < nums[t] ) {
t = i;
}
}
reverse(nums,0,t-1);
reverse(nums,t,len-1);
reverse(nums,0,len-1);
}
void reverse(vector<int> &nums,int lo,int hi) {
while (lo<hi) {
swap(nums[lo],nums[hi]);
++lo;
--hi;
}
}
};版权声明:本文为博主原创文章,未经博主允许不得转载。
lintcode Recover Rotated Sorted Array
标签:
原文地址:http://blog.csdn.net/susser43/article/details/47259409