标签:
题目描述:
Given two strings s and t, write a function to determine if t is an anagram of s. For example, s = "anagram", t = "nagaram", return true. s = "rat", t = "car", return false.
Note:
You may assume the string contains only lowercase alphabets.
直接贴代码了。
solution:
bool isAnagram(string s, string t) { if (s.size() != t.size()) return false; int counts[26] = {0}; int n = s.size(); for (int i = 0; i < n; ++i) { counts[s[i] - ‘a‘]++; counts[t[i] - ‘a‘]--; } for (int i = 0; i < 26; ++i) { if (counts[i]) return false; } return true; }
参考:https://leetcode.com/discuss/49374/2-c-solutions-with-explanations
标签:
原文地址:http://www.cnblogs.com/gattaca/p/4703006.html