低三位的数是8的倍数就可以被8整除

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>

using namespace std;

string s;bool a[10];

int main()
{
    memset(a,false,sizeof a);cin>>s;
    for(int i=0;i<s.size();i++){
        if(s[i]==‘0‘||s[i]==‘8‘) {puts("YES");printf("%c\n",s[i]);return 0;}
        if(s[i]==‘6‘&&a[1]) {puts("YES");printf("16\n");return 0;}
        if(s[i]==‘4‘&&a[2]) {puts("YES");printf("24\n");return 0;}
        if(s[i]==‘2‘&&a[3]) {puts("YES");printf("32\n");return 0;}
        if(s[i]==‘6‘&&a[5]) {puts("YES");printf("56\n");return 0;}
        if(s[i]==‘4‘&&a[6]) {puts("YES");printf("64\n");return 0;}
        if(s[i]==‘2‘&&a[7]) {puts("YES");printf("72\n");return 0;}
        if(s[i]==‘6‘&&a[9]) {puts("YES");printf("96\n");return 0;}
        a[s[i]-‘0‘]=true;
    }
    for(int i=0;i<s.size()-2;i++)
        for(int j=i+1;j<s.size()-1;j++)
            for(int k=j+1;k<s.size();k++){
                int num = (s[i]-‘0‘)*100+(s[j]-‘0‘)*10+(s[k]-‘0‘);
                if(num%8==0) {puts("YES");printf("%d\n",num);return 0;}
            }
    puts("NO");
    return 0;
}