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1 /*
2 hash+set:首先把各个字符串的哈希值保存在set容器里,然后对于查询的每一个字符串的每一位进行枚举
3 用set的find函数查找是否存在替换后的字符串,理解后并不难。另外,我想用64位的自然溢出wa了,不清楚
4 */
5 /************************************************
6 * Author :Running_Time
7 * Created Time :2015-8-5 13:05:49
8 * File Name :D.cpp
9 ************************************************/
10
11 #include <cstdio>
12 #include <algorithm>
13 #include <iostream>
14 #include <sstream>
15 #include <cstring>
16 #include <cmath>
17 #include <string>
18 #include <vector>
19 #include <queue>
20 #include <deque>
21 #include <stack>
22 #include <list>
23 #include <map>
24 #include <set>
25 #include <bitset>
26 #include <cstdlib>
27 #include <ctime>
28 using namespace std;
29
30 #define lson l, mid, rt << 1
31 #define rson mid + 1, r, rt << 1 | 1
32 typedef long long ll;
33 const int MAXN = 6e5 + 10;
34 const int INF = 0x3f3f3f3f;
35 const int MOD = 1e9 + 7;
36 const int KEY = 257;
37 char s[MAXN];
38 set<ll> S;
39 ll ha[MAXN];
40 int n, m;
41
42 void init(void) {
43 ha[0] = 1;
44 for (int i=1; i<MAXN; ++i) ha[i] = ha[i-1] * KEY % MOD;
45 }
46
47 ll get_hash(char *s) {
48 int len = strlen (s);
49 ll res = 0;
50 for (int i=0; i<len; ++i) {
51 res = (res * KEY + s[i]) % MOD;
52 }
53 return res;
54 }
55
56 bool judge(char *s) {
57 int len = strlen (s);
58 ll h = get_hash (s);
59 for (int i=0; i<len; ++i) {
60 for (ll ch=‘a‘; ch<=‘c‘; ++ch) {
61 if (ch == s[i]) continue;
62 if (S.find ((((ch-s[i]) * ha[len-i-1] + h) % MOD + MOD) % MOD) != S.end ()) return true;
63 }
64 }
65 return false;
66 }
67
68 int main(void) { //Codeforces Round #291 (Div. 2) C. Watto and Mechanism
69 init ();
70 while (scanf ("%d%d", &n, &m) == 2) {
71 S.clear ();
72 for (int i=1; i<=n; ++i) {
73 scanf ("%s", s);
74 S.insert (get_hash (s));
75 }
76 for (int i=1; i<=m; ++i) {
77 scanf ("%s", s);
78 if (judge (s)) puts ("YES");
79 else puts ("NO");
80 }
81 }
82
83 return 0;
84 }
hash+set Codeforces Round #291 (Div. 2) C. Watto and Mechanism
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原文地址:http://www.cnblogs.com/Running-Time/p/4705101.html