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一、问题:线性搜索某个数是否存在。
二、代码
#include <iostream> using namespace std; int main() { int A[] = { 9, 2, 8, 6, 7, 1, 4, 5, 3, 0 }; int target=11; bool found = false; for (int i = 0; i < 10; i++) { if (target == A[i]) { cout << "I have found it. The num is:" << i; found = true; break; } } if (found == false) { cout << "sorry! i can not found it!"; } return 0; }
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原文地址:http://www.cnblogs.com/Wanggcong/p/4705383.html