#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
#define N 10 // 带编码字符的个数,即树中叶结点的最大个数
#define M (2*N-1) // 树中总的结点数目
class HTNode{ // 树中结点的结构
public:
unsigned int weight;
unsigned int parent,lchild,rchild;
};
class HTCode{
public:
char data; // 待编码的字符
int weight; // 字符的权值
char code[N]; // 字符的编码
};
void Init(HTCode hc[], int *n){
// 初始化,读入待编码字符的个数n,从键盘输入n个字符和n个权值
int i;
printf("input n = ");
scanf("%d",&(*n));
printf("\ninput %d character\n",*n);
fflush(stdin);
for(i=1; i<=*n; ++i)
scanf("%c",&hc[i].data);
printf("\ninput %d weight\n",*n);
for(i=1; i<=*n; ++i)
scanf("%d",&(hc[i].weight) );
fflush(stdin);
}//
void Select(HTNode ht[], int k, int *s1, int *s2){
// ht[1...k]中选择parent为0,并且weight最小的两个结点,其序号由指针变量s1,s2指示
int i;
for(i=1; i<=k && ht[i].parent != 0; ++i){
; ;
}
*s1 = i;
for(i=1; i<=k; ++i){
if(ht[i].parent==0 && ht[i].weight<ht[*s1].weight)
*s1 = i;
}
for(i=1; i<=k; ++i){
if(ht[i].parent==0 && i!=*s1)
break;
}
*s2 = i;
for(i=1; i<=k; ++i){
if(ht[i].parent==0 && i!=*s1 && ht[i].weight<ht[*s2].weight)
*s2 = i;
}
}
void HuffmanCoding(HTNode ht[],HTCode hc[],int n){
// 构造Huffman树ht,并求出n个字符的编码
char cd[N];
int i,j,m,c,f,s1,s2,start;
m = 2*n-1;
for(i=1; i<=m; ++i){
if(i <= n)
ht[i].weight = hc[i].weight;
else
ht[i].parent = 0;
ht[i].parent = ht[i].lchild = ht[i].rchild = 0;
}
for(i=n+1; i<=m; ++i){
Select(ht, i-1, &s1, &s2);
ht[s1].parent = i;
ht[s2].parent = i;
ht[i].lchild = s1;
ht[i].rchild = s2;
ht[i].weight = ht[s1].weight+ht[s2].weight;
}
cd[n-1] = ‘\0‘;
for(i=1; i<=n; ++i){
start = n-1;
for(c=i,f=ht[i].parent; f; c=f,f=ht[f].parent){
if(ht[f].lchild == c)
cd[--start] = ‘0‘;
else
cd[--start] = ‘1‘;
}
strcpy(hc[i].code, &cd[start]);
}
}
int main()
{
int i,m,n,w[N+1];
HTNode ht[M+1];
HTCode hc[N+1];
Init(hc, &n); // 初始化
HuffmanCoding(ht,hc,n); // 构造Huffman树,并形成字符的编码
for(i=1; i<=n; ++i)
printf("\n%c---%s",hc[i].data,hc[i].code);
printf("\n");
return 0;
}