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099 Recover Binary Search Tree
没有按照要求用 constant space.... 用valid BST 找出两个not in order 的nodes
class Solution: def recoverTree(self, root): [fN, sN] = self.valid(root) fN.val, sN.val = sN.val, fN.val def valid(self, root): pre, fN, sN = TreeNode(-100000), None, None stack = [] while True: while root != None: stack.append(root) root = root.left if stack == []: break root = stack.pop() if pre.val >= root.val: if not fN: fN = pre sN = root else: sN = root break pre = root root = root.right return [fN, sN]
099 Recover Binary Search Tree
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原文地址:http://www.cnblogs.com/dapanshe/p/4706315.html