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Given an integer, write a function to determine if it is a power of two.
判断一个integer是否为2的幂。
1 public class Solution { 2 public static boolean isPowerOfTwo(int n) { 3 double d = n; 4 5 if(d==1){ 6 return true; 7 } 8 while(d>=2){ 9 d = d/2; 10 if(d==1){ 11 return true; 12 } 13 } 14 return false; 15 } 16 }
252 ms.
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原文地址:http://www.cnblogs.com/catcoding/p/4707298.html