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5 17
4HintThe fastest way for Farmer John to reach the fugitive cow is to move along the following path: 5-10-9-18-17, which takes 4 minutes.
bfs注意注释的几个地方,坑哭我了,,,只怪自己太菜
#include<stdio.h> #include<string.h> #include<queue> using namespace std; int vis[110000]; int n,k; struct node{ int val,d; }s,num; int bfs(){ memset(vis,0,sizeof(vis)); queue <node> Q; while(!Q.empty()) Q.pop(); s.val=n; s.d=0; vis[n]=1; Q.push(s); while(!Q.empty()){ s=Q.front(); Q.pop(); for(int i=0;i<3;i++){ if(i==0) num.val=s.val+1; if(i==1) num.val=s.val-1; if(i==2) num.val=s.val*2; num.d=s.d+1; if(num.val==k) return num.d; if(num.val<0 || num.val>110000)//原来写的num.val>k,wa了20多次,草,fuck,,, continue; //if(num.val>=0&&!vis[num.val]&&num.val<100000){//这样写num.val大于110000是,vis数组就会溢出 if(!vis[num.val]){ vis[num.val]=1; Q.push(num); } } } return -1; } int main(){ while(scanf("%d%d",&n,&k)!=EOF){ if(n>k) printf("%d\n",n-k); else if(n==k) printf("0\n"); else printf("%d\n",bfs()); } return 0; }
hdu 2717 && poj 3278 Catch That Cow
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原文地址:http://blog.csdn.net/ling_du/article/details/47314035