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Find the total area covered by two rectilinear rectangles in a 2D plane.
Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.
Assume that the total area is never beyond the maximum possible value of int.
public class Solution { public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) { //分四种场景分开讨论，寻找规律：如果发现重叠，需要减去重叠部分 //注意技巧，Math函数 if(G<=A||E>=C||B>=H||F>=D) return (C-A)*(D-B)+(G-E)*(H-F); else{ return (C-A)*(D-B)+(G-E)*(H-F)-(Math.min(C,G)-Math.max(A,E))*(Math.min(H,D)-Math.max(B,F)); } } }
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原文地址：http://www.cnblogs.com/qiaomu/p/4712264.html
