Joseph UVA 1452 Jump

 1 /*
 2     数学：约瑟夫环问题的变形，首先定义f[i]表示剩下i个人时，最后一个选出的人，有个公式：f[i] = (f[i-1] + m) % i
 3         f[1] = 0(编号从0开始)，那么类似最后一个数的求法，先找到剩2个人和剩3个人时，最后的编号，然后跟着最后一个的一起递推
 4 */
 5 /************************************************
 6 * Author        :Running_Time
 7 * Created Time  :2015-8-8 14:26:38
 8 * File Name     :UVA_1459.cpp
 9  ************************************************/
10 
11 #include <cstdio>
12 #include <algorithm>
13 #include <iostream>
14 #include <sstream>
15 #include <cstring>
16 #include <cmath>
17 #include <string>
18 #include <vector>
19 #include <queue>
20 #include <deque>
21 #include <stack>
22 #include <list>
23 #include <map>
24 #include <set>
25 #include <bitset>
26 #include <cstdlib>
27 #include <ctime>
28 using namespace std;
29 
30 #define lson l, mid, rt << 1
31 #define rson mid + 1, r, rt << 1 | 1
32 typedef long long ll;
33 const int MAXN = 5e5 + 10;
34 const int INF = 0x3f3f3f3f;
35 const int MOD = 1e9 + 7;
36 
37 void Joseph(int n, int m)    {
38     int ans1 = 0, ans2 = 0, ans3 = 0;
39     for (int i=2; i<=n; ++i)    {
40         ans1 = (ans1 + m) % i;
41         if (i == 2) {       //2个人就是0或1
42             ans2 = !ans1;
43         }
44         else if (i == 3)    {
45             ans2 = (ans2 + m) % i;
46             bool vis[3];    memset (vis, false, sizeof (vis));  
47             vis[ans1] = vis[ans2] = true;
48             for (int i=0; i<3; ++i) {
49                 if (!vis[i])    {
50                     ans3 = i;   break;
51                 }
52             }
53         }
54         else    {
55             ans2 = (ans2 + m) % i;
56             ans3 = (ans3 + m) % i;
57         }
58     }
59 
60     printf ("%d %d %d\n", ans3 + 1, ans2 + 1, ans1 + 1);
61 }
62 
63 int main(void)    {     //UVA 1452 Jump
64     int T;  scanf ("%d", &T);
65     while (T--) {
66         int n, m;   scanf ("%d%d", &n, &m);
67         Joseph (n, m);
68     }
69 
70     return 0;
71 }