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[leetcode 236]Lowest Common Ancestor of a Binary Tree

时间:2015-08-08 18:18:38      阅读:110      评论:0      收藏:0      [点我收藏+]

标签:c++   leetcode   236   lowest common ancest   

Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree.

According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”

        _______3______
       /                  ___5__          ___1__
   /      \        /         6      _2       0       8
         /           7   4

For example, the lowest common ancestor (LCA) of nodes 5 and 1 is 3. Another example is LCA of nodes 5 and 4 is 5, since a node can be a descendant of itself according to the LCA definition.

求两个叶节点的第一个公共父节点。

首先深度优先遍历整棵二叉树,记录有两个目标叶节点的两条路径。

求这两个叶节点的公共父节点,相当于求两条路径的第一个公共节点。

AC代码:

class Solution
{
public:

    void getList(TreeNode *root,TreeNode *p,TreeNode * q,deque<TreeNode*> &dq1,deque<TreeNode*> &dq2,deque<TreeNode*> &temp)
    {
        if(root==NULL)
            return ;
        else
        {
            temp.push_back(root);
            if(root==p)
                dq1=temp;
            if(root==q)
                dq2=temp;
            getList(root->left,p,q,dq1,dq2,temp);
            getList(root->right,p,q,dq1,dq2,temp);
            temp.pop_back();
        }
    }

    TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q)
    {
        deque<TreeNode*> dq1;
        deque<TreeNode*> dq2;
        deque<TreeNode*> temp;
        getList(root,p,q,dq1,dq2,temp);

        int sum1=dq1.size();
        int sum2=dq2.size();
        int x=sum1-sum2;
        deque<TreeNode*>::reverse_iterator ite1=dq1.rbegin();
        deque<TreeNode*>::reverse_iterator ite2=dq2.rbegin();
        if(x>0)
            for(int i=0; i<x; ++i)
                ++ite1;
        else
            for(int i=0; i<(-x); ++i)
                ++ite2;
        while(ite1!=dq2.rend())
        {
            if(*ite1==*ite2)
                return *ite1;
            else
            {
                ++ite1;
                ++ite2;
            }
        }
    }
};


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[leetcode 236]Lowest Common Ancestor of a Binary Tree

标签:c++   leetcode   236   lowest common ancest   

原文地址:http://blog.csdn.net/er_plough/article/details/47360235

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