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Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ public class Solution { public void deleteNode(ListNode node) { //时间复杂度就是O(1) //要删除的节点是node //直接将node->next的val值赋给node，然后删除node->next node.val=node.next.val; node.next=node.next.next; } }
[leedcode 237] Delete Node in a Linked List
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原文地址：http://www.cnblogs.com/qiaomu/p/4713773.html
