标签:leetcode c++ 237 delete node in a lin
Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is 1 -> 2 -> 3 -> 4
and you are given the third node
with value 3
, the linked list should become 1
-> 2 -> 4
after calling your function.
删除链表中的节点
class Solution { public: void deleteNode(ListNode* node) { if(node==NULL||node->next==NULL) return ; else { ListNode *temp=node->next; node->val=temp->val; node->next=temp->next; delete temp; temp=NULL; } } };
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[leetcode 237]Delete Node in a Linked List
标签:leetcode c++ 237 delete node in a lin
原文地址:http://blog.csdn.net/er_plough/article/details/47372955