标签:leetcode c++ 237 delete node in a lin
Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node
with value 3, the linked list should become 1
-> 2 -> 4 after calling your function.
删除链表中的节点
class Solution {
public:
void deleteNode(ListNode* node) {
if(node==NULL||node->next==NULL)
return ;
else
{
ListNode *temp=node->next;
node->val=temp->val;
node->next=temp->next;
delete temp;
temp=NULL;
}
}
};版权声明:本文为博主原创文章,未经博主允许不得转载。
[leetcode 237]Delete Node in a Linked List
标签:leetcode c++ 237 delete node in a lin
原文地址:http://blog.csdn.net/er_plough/article/details/47372955