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http://poj.org/problem?id=2251
/* 简单bfs,向六个方向拓展 */ /************************************************ * Author :Powatr * Created Time :2015-8-9 9:23:15 * File Name :B.cpp ************************************************/ #include <cstdio> #include <algorithm> #include <iostream> #include <sstream> #include <cstring> #include <cmath> #include <string> #include <vector> #include <queue> #include <deque> #include <stack> #include <list> #include <map> #include <set> #include <bitset> #include <cstdlib> #include <ctime> using namespace std; #define lson l, mid, rt << 1 #define rson mid + 1, r, rt << 1 | 1 typedef long long ll; const int MAXN = 1e5 + 10; const int INF = 0x3f3f3f3f; const int MOD = 1e9 + 7; int dirx[] = {1, -1, 0, 0, 0}; int diry[] = {0, 0, 1, -1, 0}; struct P{ int z, x, y; int step; }a[110]; int L, R, C; int sx, sy, sz, ex, ey, ez; queue <P> q; bool vis[40][40][40]; char maze[40][40][40]; bool ok(int z, int x, int y) { if(x >= 1 && x <= R && y >= 1 && y <= C && z >= 1 && z <= L && (maze[z][x][y] == ‘.‘ || maze[z][x][y] == ‘S‘ || maze[z][x][y] == ‘E‘) && !vis[z][x][y] ) return true; return false; } int main(){ while(~scanf("%d%d%d", &L, &R, &C) && L && R && C){ getchar(); memset(vis, false, sizeof(vis)); memset(maze, ‘.‘, sizeof(maze)); for(int i = 1; i <= L; i++){ for(int j = 1; j <= R; j++){ for(int k = 1; k <= C; k++){ scanf("%c", &maze[i][j][k]); if(maze[i][j][k] == ‘S‘){ sx = j, sy = k, sz = i; } if(maze[i][j][k] == ‘E‘){ ex = j, ey = k, ez = i; } } getchar(); } getchar(); } while(!q.empty()) q.pop(); q.push((P){sz, sx, sy, 0}); int flag = 1; while(!q.empty()){ P now = q.front(); q.pop(); int x = now.x, y = now.y, z = now.z; int step = now.step; if(!ok(z, x, y)) continue; if(x == ex && y == ey && z == ez) { printf("Escaped in %d minute(s).\n", step); flag = 0; break; } for(int i = 0; i < 4; i++){ int dx = x + dirx[i], dy = y + diry[i]; // printf("%d %d %d\n", z, dx, dy); if(ok(z, dx, dy)){ vis[z][x][y] = true; q.push((P){z, dx, dy, step+1}); } } if(ok(z+1, x, y)){ vis[z][x][y] = true; q.push((P){z+1, x, y, step+1}); } if(ok(z-1, x, y)){ vis[z][x][y] = true; q.push((P){z-1, x, y, step+1}); } } if(flag) printf("Trapped!\n"); } return 0; }
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原文地址:http://www.cnblogs.com/zero-begin/p/4714715.html