标签:
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2119
Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2205 Accepted Submission(s):
975
1 #include <iostream> 2 #include <cstdio> 3 #include <cstring> 4 5 using namespace std; 6 7 int vis[110],Map[110][110]; 8 int ok[110],n,m; 9 10 bool Find(int x) 11 { 12 for (int i=0;i<m;i++) 13 { 14 if (Map[x][i]==1&&!vis[i]) 15 { 16 vis[i]=1; 17 if (ok[i]==-1) 18 { 19 ok[i]=x; 20 return true; 21 } 22 else 23 { 24 if (Find(ok[i])==true) 25 { 26 ok[i]=x; 27 return true; 28 } 29 } 30 } 31 } 32 return false; 33 } 34 35 int main() 36 { 37 int ans; 38 while (~scanf("%d",&n)) 39 { 40 ans=0; 41 if (n==0) 42 break; 43 scanf("%d",&m); 44 memset(Map,0,sizeof(Map)); 45 memset(ok,-1,sizeof(ok)); 46 for (int i=0;i<n;i++) 47 { 48 for (int j=0;j<m;j++) 49 { 50 scanf("%d",&Map[i][j]); 51 } 52 } 53 for (int i=0;i<n;i++) 54 { 55 memset(vis,0,sizeof(vis)); 56 if (Find(i)) 57 { 58 ans++; 59 } 60 } 61 printf ("%d\n",ans); 62 } 63 return 0; 64 }
标签:
原文地址:http://www.cnblogs.com/qq-star/p/4714748.html