hdoj 1404 Digital Deletions

 1 #include<stdio.h>
 2 #include<cstring>
 3 using namespace std;
 4 const int MAXN = 1000000;
 5 int sg[MAXN];
 6 int get_lgt(int x){
 7     if(x/100000) return 6;
 8     if(x/10000) return 5;
 9     if(x/1000) return 4;
10     if(x/100) return 3;
11     if(x/10) return 2;
12     return 1;
13 }
14 void extend(int x){
15     int lgt = get_lgt(x);
16     for( int i = lgt; i >= 1; --i){
17         int m = x;
18         int base = 1;
19         for(int j = 1; j < i; ++j)
20             base *= 10;
21         int tmp = ( m % (base*10)) / base;
22         for(int j = tmp; j < 9; ++j){
23             m += base;
24             sg[m] = 1;//越界了
25         }
26     }
27     //提取每一位的数字，遍历到9
28     if( lgt!= 6 ){
29         int m = x;
30         int base = 1;
31         for( int i = lgt; i < 6;i++){
32             m *= 10;
33             for(int j = 0; j < base; ++j)
34                 sg[m+j] = 1;
35             base *= 10;
36         }
37     }
38 }
39 // sg[0] = 1;N态 sg[1] = 0;P态
40 // 终态是P态，可以移动到P态的是N态，所有移动都会导致N态的是P态
41 void init(){
42     memset(sg,0,sizeof(sg));
43     sg[0] = 1;
44     for(int i = 1; i < MAXN; ++i)
45         if(!sg[i])//N态
46             extend(i);
47 }
48 int main(){
49         freopen("test.out","r",stdin);
50     freopen("mtest.out","w",stdout);
51     init();
52     char str[8];
53     int lgt;
54     int n;
55     while(~scanf("%s",&str)){
56         n = 0;
57         if( str[0]==‘0‘ )
58             printf("Yes\n");
59         else{
60             lgt = strlen(str);
61             for(int i = 0; i < lgt; ++i){
62                 n *= 10;
63                 n += str[i]-‘0‘;
64             }//字符串转化为整数
65             if(sg[n])
66                 printf("Yes\n");
67             else
68                 printf("No\n");
69         }
70     }
71 }