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杭电2009(求数列的和)
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 55907 Accepted Submission(s): 34435
1 #include <cstdio> 2 #include <iostream> 3 #include <cmath> 4 using namespace std; 5 int main() 6 { 7 double a,b,k; 8 while(scanf("%lf %lf",&a,&b) != EOF) 9 { 10 11 if(a >= 10000 && b >= 1000) 12 { 13 break; 14 } 15 k=0; 16 while (b--) 17 { 18 k = k + a; 19 a = sqrt(a); 20 } 21 printf("%.2f\n",k); 22 } 23 return 0;
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原文地址:http://www.cnblogs.com/sxmcACM/p/4718833.html