标签:
3 1 2 1 0 1 3 2 0 2 3 4 0 3 1 2 1 0 1 3 2 0 2 3 4 1 3 1 2 1 0 1 3 2 1 2 3 4 1 0
3 1 0
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <queue>
#include <cmath>
using namespace std;
int per[1100];
int N, M;
struct node{
int u, v, w;
};
node edge[110000];
int cmp(node a, node b){
return a.w < b.w;
}
void init(){
for(int i = 1; i <= N; ++i)
per[i] = i;
}
int find(int x){
if(x == per[x])
return x;
return per[x] = find(per[x]);
}
bool join (int x, int y){
int fx = find(x);
int fy = find(y);
if(fx != fy){
per[fx] = fy;
return true;
}
return false;
}
int main (){
while(scanf("%d", &N), N){
M = N * (N - 1) / 2;
int flag;
for(int i = 0; i < M; ++i){
scanf("%d%d%d%d", &edge[i].u, &edge[i].v, &edge[i].w, &flag);
if(flag)
edge[i].w = 0;
}
sort(edge, edge + M, cmp);
int sum = 0;
init();
for(int i = 0; i < M; ++i){
if(join(edge[i].u, edge[i].v))
sum += edge[i].w;
}
printf("%d\n", sum);
}
return 0;
}
版权声明:本文为博主原创文章,未经博主允许不得转载。
HDU 1879--继续畅通工程【kruskal && 最小生成树 && 水题】
标签:
原文地址:http://blog.csdn.net/hpuhjh/article/details/47405089