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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 798 Accepted Submission(s): 329
1 #include <cmath> 2 #include <cstdio> 3 #include <cstring> 4 #include <iostream> 5 #include <algorithm> 6 using namespace std; 7 int father[200200]; 8 int n, m; 9 struct rode 10 { 11 int x, y, w; 12 } num[200200], shu[200200]; 13 14 bool cmp(rode x, rode y) 15 { 16 return x.w > y.w; 17 } 18 19 bool cpm(rode x, rode y) 20 { 21 return x.w < y.w; 22 } 23 24 void init() 25 { 26 for(int i = 0; i < n; i++) 27 father[i] = i; 28 } 29 30 int find(int a) 31 { 32 if(a == father[a]) 33 return a; 34 else 35 return father[a] = find(father[a]); 36 } 37 38 bool mercy(int a, int b) 39 { 40 int q = find(a); 41 int p = find(b); 42 if(q != p) 43 { 44 father[q] = p; 45 return true; 46 } 47 else 48 return false; 49 } 50 51 int main() 52 { 53 while(~scanf("%d %d", &n, &m), n+m) 54 { 55 init(); int sum = 0; 56 for(int i = 0; i < m; i++) 57 { 58 scanf("%d %d %d", &num[i].x, &num[i].y, &num[i].w); 59 shu[i].x = num[i].x; shu[i].y = num[i].y; shu[i].w = num[i].w; 60 sum += num[i].w; 61 } 62 /*int sum = 0; 63 sort(num, num + m, cmp); 64 for(int i = 0; i < m; i++) 65 { 66 if(mercy(num[i].x, num[i].y)) 67 sum += num[i].w; 68 }*/ 69 int total = 0; 70 sort(shu, shu + m, cpm); 71 for(int i = 0; i < m; i++) 72 { 73 if(mercy(shu[i].x, shu[i].y)) 74 total += shu[i].w; 75 } 76 printf("%d\n", abs(sum - total)); 77 } 78 return 0; 79 }
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原文地址:http://www.cnblogs.com/fengshun/p/4722458.html