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Time Limit: 1000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 3273 Accepted Submission(s):
1320
#include<stdio.h>
#include<string.h>
#define INF 0x3f3f3f
#define min(x,y)(x<y?x:y)
#define MAX 1010
int n,m;
int map[MAX][MAX];
int dis[MAX][MAX];
void init()
{
int i,j;
for(i=1;i<=n;i++)
for(j=1;j<=n;j++)
{
map[i][j]=i==j?0:INF;
dis[i][j]=i==j?0:INF;
}
}
void getmap()
{
int i,j;
for(i=1;i<=m;i++)
{
int a,b,c;
scanf("%d%d%d",&a,&b,&c);
if(map[a][b]>c)
map[a][b]=map[b][a]=dis[a][b]=dis[b][a]=c;
}
}
void floyd()
{
int i,j,k;
int sum=INF;
for(k=1;k<=n;k++)
{
for(i=1;i<k;i++) //求最小环
for(j=1;j<i;j++)
sum=min(sum,map[i][k]+map[k][j]+dis[j][i]);
for(i=1;i<=n;i++)//更新最短路径
for(j=1;j<=n;j++)
dis[i][j]=min(dis[i][j],dis[i][k]+dis[k][j]);
}
if(sum==INF)
printf("It‘s impossible.\n");
else
printf("%d\n",sum);
}
int main()
{
while(scanf("%d%d",&n,&m)!=EOF)
{
init();
getmap();
floyd();
}
return 0;
}
hdoj 1599 find the mincost route【floyd+最小环】
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原文地址:http://www.cnblogs.com/tonghao/p/4728324.html