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Maze

4 4 9
9
1 2 1 3 2
1 2 2 2 0
2 1 2 2 0
2 1 3 1 0
2 3 3 3 0
2 4 3 4 1
3 2 3 3 0
3 3 4 3 0
4 3 4 4 0
2
2 1 2
4 2 1

把 map 数组初始化为 -1 了 ，测试样例都过不了，调试了2个多小时才发现 ，真是越来越都比了。

还要注意：一个地方可能多多个不同类型的钥匙，坑啊

#include <cstdio>
#include <cstring>
#include <algorithm>
#include <queue>
#define maxn 55
using namespace std;

int vis[maxn][maxn][1 << 11];
int map[maxn][maxn][maxn][maxn];
int keynum[maxn][maxn][11];//记录这个地点有哪几种钥匙
int dir[4][2] = {0, 1, 0, -1, 1, 0, -1, 0};
int n, m, p, s, k;//p代表有几种钥匙。

struct node{
    int x, y ,step, key;
    friend bool operator  < (node a , node b)
    {
        return a.step > b.step;
    }
};

int check(node a, node b)
{
    if(b.x <= 0 || b.x > n || b.y <= 0 || b.y > m)
        return 0;
    if(map[a.x][a.y][b.x][b.y] == 0)
        return 0;
    return 1;
}

int BFS(){
    priority_queue<node>q;
    node now, next;
    now.x = 1;
    now.y = 1;
    now.step = 0;
    now.key = 0;
    for(int j = 1; j <= 10; ++j){// 起点有钥匙
        if(keynum[now.x][now.y][j])
            now.key = now.key | (1 << j);
    }
    q.push(now);
    vis[now.x][now.y][now.key] = 1;
    while(!q.empty()){
        now = q.top();
        q.pop();
        if(now.x == n && now.y == m){
            return now.step;
        }
        for(int i = 0; i < 4; ++i){
            next.x = now.x + dir[i][0];
            next.y = now.y + dir[i][1];
            next.step = now.step + 1;
            //printf("--%d\n", next.step);
            next.key = now.key;
            if(check(now, next)){//now 和 next 之间没有墙
                if(map[now.x][now.y][next.x][next.y] > 0){ //now 和 next 中间有门
                    if(next.key & (1 << map[now.x][now.y][next.x][next.y])){//有这个门的钥匙，能通过这个门到达next
                        for(int j = 1; j <= 10; ++j){ //判断点next是不是有钥匙
                            if(keynum[next.x][next.y][j])
                                next.key = next.key | (1 << j);
                        }
                        if(!vis[next.x][next.y][next.key]){
                            vis[next.x][next.y][next.key] = 1;
                            q.push(next);
                        }
                    }
                }
                else {
                    for(int j = 1; j <= 10; ++j){//判断点next是不是有钥匙
                        if(keynum[next.x][next.y][j]){
                            next.key = next.key | (1 << j);
                        }
                    }
                    if(!vis[next.x][next.y][next.key]){
                            vis[next.x][next.y][next.key] = 1;
                            q.push(next);
                    }
                }
            }
        }
    }
    return -1;
}

int main (){
    while(scanf("%d%d%d", &n, &m, &p) != EOF){
        scanf("%d", &k);
        memset(map, -1, sizeof(map));
        memset(vis, 0, sizeof(vis));
        memset(keynum, 0, sizeof(keynum));
        while(k--){
            int x1, y1, x2, y2, t;
            scanf("%d%d%d%d%d", &x1, &y1, &x2, &y2, &t);
            map[x1][y1][x2][y2] = t;
            map[x2][y2][x1][y1] = t;
        }
        scanf("%d", &s);
        while(s--){
            int x, y, t;
            scanf("%d%d%d", &x, &y, &t);
            keynum[x][y][t] = 1;
        }
        printf("%d\n", BFS());
    }
    return 0;
}

HDU 5094 --Maze【BFS && 状态压缩】

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原文地址：http://blog.csdn.net/hpuhjh/article/details/47627535