标签:
#include<stdio.h>
#include<string.h>
#include<queue>
#include<vector>
using namespace std;
const int N=200000+5;
const int inf=1<<24;
struct Edge
{
int from,to,cap,flow;
};
vector<Edge>edges;
vector<int>G[N];
int n,m,s,t;
int vis[N];
int d[N];
int cur[N];
void AddEdge(int from,int to,int cap)
{
Edge tp;
tp.from=from,tp.to=to,tp.cap=cap,tp.flow=0;
edges.push_back(tp);
tp.from=to,tp.to=from,tp.cap=0,tp.flow=0;
edges.push_back(tp);
int g_size=edges.size();
G[from].push_back(g_size-2);
G[to].push_back(g_size-1);
}
bool BFS()
{
memset(vis,0,sizeof(vis));
queue<int>Q;
Q.push(s);
d[s]=0;
vis[s]=1;
while(!Q.empty())
{
int x=Q.front();
Q.pop();
for(int i=0; i<G[x].size(); i++)
{
Edge &e=edges[G[x][i]];
if(!vis[e.to]&&e.cap>e.flow)
{
vis[e.to]=1;
d[e.to]=d[x]+1;
Q.push(e.to);
}
}
}
return vis[t];
}
int DFS(int x,int a)
{
if(x==t||a==0) return a;
int flow=0,f;
for(int &i=cur[x]; i<G[x].size(); i++)
{
Edge &e=edges[G[x][i]];
if(d[x]+1==d[e.to]&&(f=DFS(e.to,min(a,e.cap-e.flow)))>0)
{
e.flow+=f;
edges[G[x][i]^1].flow-=f;
flow+=f;
a-=f;
if(a==0) break;
}
}
return flow;
}
int Maxflow(int st,int ed)
{
int flow=0;
while(BFS())
{
memset(cur,0,sizeof(cur));
flow+=DFS(st,inf);
}
return flow;
}
int main()
{
int i,u,v,a,b,c;
while(~scanf("%d%d",&n,&m))
{
edges.clear();
for(i=0; i<n+1; i++) G[i].clear();
s=0;t=n+1;
for(i=1;i<=n;i++)
{
scanf("%d%d",&a,&b);
AddEdge(0,i,a);
AddEdge(i,n+1,b);
}
for(i=0;i<m;i++)
{
scanf("%d%d%d",&u,&v,&c);
AddEdge(u,v,c);
AddEdge(v,u,c);
}
printf("%d\n",Maxflow(s,t));
}
return 0;
}
版权声明:本文为博主原创文章,未经博主允许不得转载。
poj 3469 Dual Core CPU 最大流最小割定理
标签:
原文地址:http://blog.csdn.net/xinag578/article/details/47701793