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Valid Sudoku

时间:2015-08-16 16:28:34      阅读:100      评论:0      收藏:0      [点我收藏+]

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题目:

Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules.

The Sudoku board could be partially filled, where empty cells are filled with the character ‘.‘.

技术分享

A partially filled sudoku which is valid.

 

Note:
A valid Sudoku board (partially filled) is not necessarily solvable. Only the filled cells need to be validated.

分析:题目其实没有难度,按照它的要求做就行了。代码已通过检测

 1 def isValidSudoku(self, board):
 2         row = 0
 3         column = 0
 4         flag = 0
 5         
 6         #查看每一行是否符合规则
 7         while row < 9:
 8             i = 0
 9             temp = []
10             while i < 9:
11                 if board[row][i] != .:
12                     if board[row][i] not in temp:
13                         temp.append(board[row][i])
14                         i += 1
15                     else:
16                         flag = 1
17                         break
18                 else:
19                     i += 1
20             
21             if flag == 1:
22                 break
23             else:
24                 row += 1
25                 
26         if flag == 1:
27             return False
28         else:
29             #查看每一行是否符合规则
30             while column < 9:
31                 j = 0
32                 temp = []
33                 while j < 9:
34                     if board[j][column] != .:
35                         if board[j][column] not in temp:
36                             temp.append(board[j][column])
37                             j += 1
38                         else:
39                             flag = 1
40                             break
41                     else:
42                         j += 1
43                 
44                 if flag == 1:
45                     break
46                 else:
47                     column += 1
48             
49             if flag == 1:
50                 return False
51             else:
52                 #查看每个九宫格是否符合规则
53                 row = 0
54                 column = 0
55                 while row < 7:
56                     while column < 7:
57                         r = 0
58                         c = 0
59                         temp = []
60                         while r < 3:
61                             while c < 3:
62                                 if board[row+r][column+c] != .:
63                                     if board[row+r][column+c] not in temp:
64                                         temp.append(board[row+r][column+c])
65                                         c += 1
66                                     else:
67                                         flag = 1
68                                         break
69                                 else:
70                                     c += 1
71                             if flag == 1:
72                                 break
73                             else:
74                                 r += 1
75                                 c = 0
76                         
77                         if flag == 1:
78                             break
79                         else:
80                             column += 3
81                     
82                     if flag == 1:
83                         break
84                     else:
85                         row += 3
86                         column = 0
87             
88             if flag == 1:
89                 return False
90             else:
91                 return True

 

Valid Sudoku

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原文地址:http://www.cnblogs.com/tingyu-yudeyinji/p/4734461.html

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