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Time Limit: 1000MS | Memory Limit: 10000K | |
Total Submissions: 53679 | Accepted: 15738 |
Description
Input
Output
Sample Input
100 7 1 101 1 2 1 2 2 2 3 2 3 3 1 1 3 2 3 1 1 5 5
Sample Output
3
并查集 考虑到3种情况 0 1 2分别代表c b a 即1吃0 2吃1 0吃2
/* *********************************************** Author :pk28 Created Time :2015/8/16 16:28:41 File Name :4.cpp ************************************************ */ #include <iostream> #include <cstring> #include <cstdlib> #include <stdio.h> #include <algorithm> #include <vector> #include <queue> #include <set> #include <map> #include <string> #include <math.h> #include <stdlib.h> #include <iomanip> #include <list> #include <deque> #include <stack> #define ull unsigned long long #define ll long long #define mod 90001 #define INF 0x3f3f3f3f #define maxn 50000+10 #define cle(a) memset(a,0,sizeof(a)) const ull inf = 1LL << 61; const double eps=1e-5; using namespace std; bool cmp(int a,int b){ return a>b; } int n,k,ans; int fa[maxn],d[maxn]; void init(){ for(int i=1;i<=n;i++){ d[i]=0; fa[i]=i; } ans=0; } int findfa(int x){ if(x==fa[x])return x; else{ int root=findfa(fa[x]); d[x]=(d[x]+d[fa[x]])%3; fa[x]=root; return fa[x]; } } void Union(int a,int b,int t){ int x=findfa(a); int y=findfa(b); if(x==y){ if(t==1&&(d[a]!=d[b]))ans++; if(t==2){ if(d[a]==2&&d[b]!=1)ans++; if(d[a]==1&&d[b]!=0)ans++; if(d[a]==0&&d[b]!=2)ans++; } return ; } fa[x]=y; if(t==1) d[x]=(d[b]-d[a]+3)%3; else d[x]=(d[b]-d[a]+1+3)%3; } int main() { #ifndef ONLINE_JUDGE freopen("in.txt","r",stdin); #endif //freopen("out.txt","w",stdout); int t,a,b; cin>>n>>k; init(); for(int i=1;i<=k;i++){ scanf("%d %d %d",&t,&a,&b); if(a>n||b>n||(t==2&&a==b)){ans++;continue;} Union(a,b,t); } printf("%d\n",ans); return 0; }
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原文地址:http://www.cnblogs.com/pk28/p/4735344.html