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Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 9122 Accepted Submission(s):
3213
#include<stdio.h>
#include<string.h>
#define MAX 1010
#define INF 0x3f3f3f
#define DD double
int n,m;
DD map[MAX][MAX],low[MAX];
int vis[MAX];
void getmap()
{
int i,j;
DD a;
memset(map,0,sizeof(map));
for(i=1;i<=n;i++)
{
for(j=1;j<=n;j++)
{
scanf("%lf",&a);
map[i][j]=a;
}
}
}
void dijkstra(int a,int b)
{
int i,j,next;
DD max;
for(i=1;i<=n;i++)
low[i]=map[a][i];
memset(vis,0,sizeof(vis));
vis[a]=1;
for(i=1;i<n;i++)
{
max=0;
next=a;
for(j=1;j<=n;j++)
{
if(!vis[j]&&max<low[j])
{
next=j;
max=low[j];
}
}
vis[next]=1;
for(j=1;j<=n;j++)
{
if(!vis[j]&&low[j]<low[next]*map[next][j]) //此处的求法有所不同
low[j]=low[next]*map[next][j];
}
}
if(low[b]==0)
printf("What a pity!\n");
else
printf("%.3lf\n",low[b]);
}
void solve()
{
scanf("%d",&m);
for(int i=1;i<=m;i++)
{
int a,b;
scanf("%d%d",&a,&b);
if(a==b)
printf("1.000\n");//注意自己到自己的情况
else
dijkstra(a,b);
}
}
int main()
{
int i,j;
while(scanf("%d",&n)!=EOF)
{
getmap();
solve();
}
return 0;
}
hdoj 1596 find the safest road【最短路变形,求最大安全系数】
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原文地址:http://www.cnblogs.com/tonghao/p/4737576.html